Calculating Fork Length

Discussion in 'Motorcycle Technical Discussion' started by rricciardi, Jan 24, 2005.

  1. rricciardi

    rricciardi Guest

    Hey Guys,
    I have just bought a Carolina Custom rigid frame. It has 41 degree
    rake, 6" up, and 6" out. I am thinking of an old school look by using a
    springer front end. Can someone tell me the correct way to calculate
    how long a front end I will need to achieve the correct trail of 4"?
     
    rricciardi, Jan 24, 2005
    #1
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  2. a springer front end. Can someone tell me the correct way to calculate
    how long a front end I will need to achieve the correct trail of 4"?

    Do you do trigonometry? I don't use it much, so if I'm wrong, go ahead
    and laugh at me, but the trail result I get from calculating a 41
    degree rake seem to agree with what I remember...

    To find the required lenghth of your fork, you'll have to subtract one
    triangle's hypotenuse from a larger triangle's hyspotenuse...

    Remember from trigonomtry, the sum of all the angles in a triangle is
    180 degrees. One of the angles in a right triangle is always 90
    degrees. Your design fork angle is 41 degrees, so

    180 minus ( 90 + 41 ) = 49 degrees

    You're probably going to use a 3.00 x 21 front tire with a wheel radius
    of 21 divided by 2 = 10.5 + 3 = 13.50 inches

    The front axle will be 13.50 inches above the ground. that's the only
    known side of our first triangle (call it "z", )

    sin 49 degrees = 13.50 inches divided by unknown hypotenuse (call it
    "x"), so

    x = z divided by sin 49 degrees
    x = 17.88 inches ( long side, or hypotenuse of your smaller triangle)

    Now we want the trail, the second unknown side in our first triangle
    (call it "y")

    y = z divided by tan 49
    y = 11.74 inches (that's a bunch of trail, but keep reading)

    So there we have the dimensions of our first triangle...

    Find a nice flat surface so you can get reasonably accurate
    measurements. Set your frame on blocks so the slots that the rear axle
    is going to go through are at the height of exactly half the diameter
    of your rear wheel and tire assembly...

    Using the biggest protractor you can get, adjust the steering head
    angle by putting blocks under the frame until you get exactly 41
    degrees and then measure the height of the top of the steering neck,
    plus whatever you think the thickness of the upper triple clamp is
    going to be...

    That will be the known side of the second, larger triangle...

    Then proceed to calculate the hypotenuse of your second triangle, the
    larger one, just like we did above, and subtract the length of the
    first hypotenuse from the second hypotenuse. That's the length of your
    fork leg if it was a solid strut...

    I know, you said you wanted to keep your trail at about 4 inches, and
    use a *springer* front end. The length of the lower link from the pivot
    point to the center of the front axle will have to be subtracted from
    the trail I calculated in the first triangle, and the triple clamp off
    set will have to be subtracted too.

    In order to get your trail at 4 inches, the total offset for the front
    link plus the triple clamps would have to be
    11.74 minus 4 = 7.74 inches...
     
    krusty kritter, Jan 25, 2005
    #2
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  3. rricciardi

    rricciardi Guest

    Wow. Thanks for the lesson !!!!!

     
    rricciardi, Jan 25, 2005
    #3

  4. See this? This is a snipped posting ;-)
     
    The Older Gentleman, Jan 25, 2005
    #4
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