Conversion help: mm BTDC to degrees BTDC

Discussion in 'Motorcycle Technical Discussion' started by Ted Bennett, May 4, 2004.

  1. Ted Bennett

    Ted Bennett Guest

    Anybody want to take a crack at it? (If you don't know for what BTDC is
    an acronym, don't bother trying to answer.)

    My bike's points open at 0.8 mm BTDC, and I want to measure that with a
    degree wheel and strobe light. I trust dymanic timing before static,
    because the points are at the end of a four-gear drive train. Lash, you
    know.

    Ted
     
    Ted Bennett, May 4, 2004
    #1
    1. Advertisements

  2. Ted Bennett

    dogalone Guest

    not positive, but pretty sure the differentiation of mark vs mark (with the
    strobe) exceeds by far the 0.80 mm accuracy of the dial indicator. it has
    been my experience that whatever gear lash is involved is taken up by only
    checking/setting the distance by turning the engine in the normal rotation
     
    dogalone, May 4, 2004
    #2
    1. Advertisements

  3. Ted Bennett

    Dan Carter Guest

    Here's the formula for x, piston position relative to TDC:

    r: stroke / 2
    l: length of connecting rod
    theta: angular position of crankshaft from TDC

    x = l + r - r * cos(theta) - sqrt(l^2 - (r * sin(theta))^2)

    I'm not bright enough to simplify that, let alone to solve for theta, so
    I wrote an HP48 program that calculates x from l, r, and theta. I would
    then try solutions using a binary search type algorithm (manually) to
    home in on a value that yields .8mm.

    For info I just ran a test case with stroke of 60mm and rod length of
    120mm and came up with 11.869° for 8mm BTDC in about a minute.

    If you post stroke and connecting rod length, I can give you an answer.
     
    Dan Carter, May 4, 2004
    #3
  4. Ted Bennett

    the fly Guest


    Turn the crank steadily in the normal direction of rotation,
    and gear lash, etc. is not a factor.
    Measurement of piston travel is a more accurate way of setting
    timing than measuring crank rotation in degrees, provided that the
    spark plug hole is parallel to the cylinder centerline.
    It takes a hell of a trigonometry exercise to make a table
    equating piston travel with degrees of crank rotation. The point of
    diminishing returns is rapidly surpassed.
     
    the fly, May 6, 2004
    #4
  5. Ted Bennett

    Lee Guest

  6. Ted Bennett

    Ted Bennett Guest

    Ted Bennett, May 7, 2004
    #6
  7. Ted Bennett

    Ted Bennett Guest

    Can't turn it steadily because of resistance from compression and
    springs.
    Right, that's the problem. The spark plug hole is off-center in the
    roof of a hemispherical chamber.
    I want to be able to use a degree wheel and strobe so I can experiment
    with various ignition timings. Anyway, I found a formula (yes, it's
    complex, but that doesn't scare me) and now all I need is the length of
    my connecting rod. Not easy to find for some reason, and I don't feel
    like taking the motor apart to find out by direct measurement.
     
    Ted Bennett, May 7, 2004
    #7
  8. Uhhh.. had you ever considered removing the spark plugs ?
    Rumor has it that this reduces compression greatly.
     
    Rob Kleinschmidt, May 8, 2004
    #8
    1. Advertisements

Ask a Question

Want to reply to this thread or ask your own question?

You'll need to choose a username for the site, which only take a couple of moments (here). After that, you can post your question and our members will help you out.